Optimal. Leaf size=122 \[ -\frac {3 \tan ^{-1}\left (\frac {\sqrt {c} \tan (e+f x)}{\sqrt {2} \sqrt {c-c \sec (e+f x)}}\right )}{4 \sqrt {2} a c^{3/2} f}-\frac {3 \tan (e+f x)}{4 a f (c-c \sec (e+f x))^{3/2}}+\frac {\tan (e+f x)}{f (a \sec (e+f x)+a) (c-c \sec (e+f x))^{3/2}} \]
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Rubi [A] time = 0.21, antiderivative size = 122, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 34, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {3960, 3796, 3795, 203} \[ -\frac {3 \tan ^{-1}\left (\frac {\sqrt {c} \tan (e+f x)}{\sqrt {2} \sqrt {c-c \sec (e+f x)}}\right )}{4 \sqrt {2} a c^{3/2} f}-\frac {3 \tan (e+f x)}{4 a f (c-c \sec (e+f x))^{3/2}}+\frac {\tan (e+f x)}{f (a \sec (e+f x)+a) (c-c \sec (e+f x))^{3/2}} \]
Antiderivative was successfully verified.
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Rule 203
Rule 3795
Rule 3796
Rule 3960
Rubi steps
\begin {align*} \int \frac {\sec (e+f x)}{(a+a \sec (e+f x)) (c-c \sec (e+f x))^{3/2}} \, dx &=\frac {\tan (e+f x)}{f (a+a \sec (e+f x)) (c-c \sec (e+f x))^{3/2}}+\frac {3 \int \frac {\sec (e+f x)}{(c-c \sec (e+f x))^{3/2}} \, dx}{2 a}\\ &=-\frac {3 \tan (e+f x)}{4 a f (c-c \sec (e+f x))^{3/2}}+\frac {\tan (e+f x)}{f (a+a \sec (e+f x)) (c-c \sec (e+f x))^{3/2}}+\frac {3 \int \frac {\sec (e+f x)}{\sqrt {c-c \sec (e+f x)}} \, dx}{8 a c}\\ &=-\frac {3 \tan (e+f x)}{4 a f (c-c \sec (e+f x))^{3/2}}+\frac {\tan (e+f x)}{f (a+a \sec (e+f x)) (c-c \sec (e+f x))^{3/2}}-\frac {3 \operatorname {Subst}\left (\int \frac {1}{2 c+x^2} \, dx,x,\frac {c \tan (e+f x)}{\sqrt {c-c \sec (e+f x)}}\right )}{4 a c f}\\ &=-\frac {3 \tan ^{-1}\left (\frac {\sqrt {c} \tan (e+f x)}{\sqrt {2} \sqrt {c-c \sec (e+f x)}}\right )}{4 \sqrt {2} a c^{3/2} f}-\frac {3 \tan (e+f x)}{4 a f (c-c \sec (e+f x))^{3/2}}+\frac {\tan (e+f x)}{f (a+a \sec (e+f x)) (c-c \sec (e+f x))^{3/2}}\\ \end {align*}
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Mathematica [C] time = 1.42, size = 183, normalized size = 1.50 \[ \frac {e^{-\frac {1}{2} i (e+f x)} \csc (e+f x) \left (\cos \left (\frac {1}{2} (e+f x)\right )+i \sin \left (\frac {1}{2} (e+f x)\right )\right ) \left (-8 (\cos (e+f x)-3)+\frac {6 \sqrt {2} e^{-i (e+f x)} \left (-1+e^{i (e+f x)}\right )^2 \left (1+e^{i (e+f x)}\right ) \tanh ^{-1}\left (\frac {1+e^{i (e+f x)}}{\sqrt {2} \sqrt {1+e^{2 i (e+f x)}}}\right )}{\sqrt {1+e^{2 i (e+f x)}}}\right )}{32 a c f \sqrt {c-c \sec (e+f x)}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.51, size = 329, normalized size = 2.70 \[ \left [-\frac {3 \, \sqrt {2} \sqrt {-c} {\left (\cos \left (f x + e\right ) - 1\right )} \log \left (\frac {2 \, \sqrt {2} {\left (\cos \left (f x + e\right )^{2} + \cos \left (f x + e\right )\right )} \sqrt {-c} \sqrt {\frac {c \cos \left (f x + e\right ) - c}{\cos \left (f x + e\right )}} + {\left (3 \, c \cos \left (f x + e\right ) + c\right )} \sin \left (f x + e\right )}{{\left (\cos \left (f x + e\right ) - 1\right )} \sin \left (f x + e\right )}\right ) \sin \left (f x + e\right ) + 4 \, {\left (\cos \left (f x + e\right )^{2} - 3 \, \cos \left (f x + e\right )\right )} \sqrt {\frac {c \cos \left (f x + e\right ) - c}{\cos \left (f x + e\right )}}}{16 \, {\left (a c^{2} f \cos \left (f x + e\right ) - a c^{2} f\right )} \sin \left (f x + e\right )}, \frac {3 \, \sqrt {2} \sqrt {c} {\left (\cos \left (f x + e\right ) - 1\right )} \arctan \left (\frac {\sqrt {2} \sqrt {\frac {c \cos \left (f x + e\right ) - c}{\cos \left (f x + e\right )}} \cos \left (f x + e\right )}{\sqrt {c} \sin \left (f x + e\right )}\right ) \sin \left (f x + e\right ) - 2 \, {\left (\cos \left (f x + e\right )^{2} - 3 \, \cos \left (f x + e\right )\right )} \sqrt {\frac {c \cos \left (f x + e\right ) - c}{\cos \left (f x + e\right )}}}{8 \, {\left (a c^{2} f \cos \left (f x + e\right ) - a c^{2} f\right )} \sin \left (f x + e\right )}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: NotImplementedError} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 2.14, size = 266, normalized size = 2.18 \[ \frac {\left (-1+\cos \left (f x +e \right )\right )^{2} \left (\left (-\frac {2 \cos \left (f x +e \right )}{1+\cos \left (f x +e \right )}\right )^{\frac {5}{2}} \cos \left (f x +e \right )+\left (-\frac {2 \cos \left (f x +e \right )}{1+\cos \left (f x +e \right )}\right )^{\frac {5}{2}}+\cos \left (f x +e \right ) \left (-\frac {2 \cos \left (f x +e \right )}{1+\cos \left (f x +e \right )}\right )^{\frac {3}{2}}-\left (-\frac {2 \cos \left (f x +e \right )}{1+\cos \left (f x +e \right )}\right )^{\frac {3}{2}}-3 \cos \left (f x +e \right ) \sqrt {-\frac {2 \cos \left (f x +e \right )}{1+\cos \left (f x +e \right )}}-3 \cos \left (f x +e \right ) \arctan \left (\frac {1}{\sqrt {-\frac {2 \cos \left (f x +e \right )}{1+\cos \left (f x +e \right )}}}\right )+3 \sqrt {-\frac {2 \cos \left (f x +e \right )}{1+\cos \left (f x +e \right )}}+3 \arctan \left (\frac {1}{\sqrt {-\frac {2 \cos \left (f x +e \right )}{1+\cos \left (f x +e \right )}}}\right )\right )}{2 a f \left (\frac {c \left (-1+\cos \left (f x +e \right )\right )}{\cos \left (f x +e \right )}\right )^{\frac {3}{2}} \sin \left (f x +e \right )^{3} \left (-\frac {2 \cos \left (f x +e \right )}{1+\cos \left (f x +e \right )}\right )^{\frac {3}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sec \left (f x + e\right )}{{\left (a \sec \left (f x + e\right ) + a\right )} {\left (-c \sec \left (f x + e\right ) + c\right )}^{\frac {3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {1}{\cos \left (e+f\,x\right )\,\left (a+\frac {a}{\cos \left (e+f\,x\right )}\right )\,{\left (c-\frac {c}{\cos \left (e+f\,x\right )}\right )}^{3/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {\sec {\left (e + f x \right )}}{- c \sqrt {- c \sec {\left (e + f x \right )} + c} \sec ^{2}{\left (e + f x \right )} + c \sqrt {- c \sec {\left (e + f x \right )} + c}}\, dx}{a} \]
Verification of antiderivative is not currently implemented for this CAS.
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